What are the solutions to the equation x^2-18x=-32 ?

The solutions to the equation x^2-18x=-32 are x=16,x=2

Find the zeros of x^2-18x=-32

The zeros of x^2-18x=-32 are x=16,x=2

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x^{2} - 18 x = - 32

x = 16, x = 2

Solution steps

x^{2} - 18 x = - 32

Move

32

to the left side

x^{2} - 18 x + 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- ( - 18 ) \pm ( - 18 ) ^{2} - 4 \cdot 1 \cdot 32}{2 \cdot 1}

(- 18)^{2} - 4 \cdot 1 \cdot 32 = 14

x_{1, 2} = \frac{- ( - 18 ) \pm 14}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- ( - 18 ) + 14}{2 \cdot 1}, x_{2} = \frac{- ( - 18 ) - 14}{2 \cdot 1}

x = \frac{- ( - 18 ) + 14}{2 \cdot 1} : 16

x = \frac{- ( - 18 ) - 14}{2 \cdot 1} : 2

The solutions to the quadratic equation are:

x = 16, x = 2

- 16 t^{2} + 70 t - 55 = 0

4 (2 y + 6) = - 4 y

25 x^{2} = 4

- 2 (x + 4) + 6 = - 3

3 x - 4 > x + 6

What are the solutions to the equation x^2-18x=-32 ?
The solutions to the equation x^2-18x=-32 are x=16,x=2
Find the zeros of x^2-18x=-32
The zeros of x^2-18x=-32 are x=16,x=2