What are the solutions to the equation x^2+6x-27=0 ?

The solutions to the equation x^2+6x-27=0 are x=3,x=-9

Find the zeros of x^2+6x-27=0

The zeros of x^2+6x-27=0 are x=3,x=-9

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x^{2} + 6 x - 27 = 0

x = 3, x = - 9

Solution steps

x^{2} + 6 x - 27 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 1 \cdot ( - 27 )}{2 \cdot 1}

6^{2} - 4 \cdot 1 \cdot (- 27) = 12

x_{1, 2} = \frac{- 6 \pm 12}{2 \cdot 1}

Separate the solutions

x_{1} = \frac{- 6 + 12}{2 \cdot 1}, x_{2} = \frac{- 6 - 12}{2 \cdot 1}

x = \frac{- 6 + 12}{2 \cdot 1} : 3

x = \frac{- 6 - 12}{2 \cdot 1} : - 9

The solutions to the quadratic equation are:

x = 3, x = - 9

u^{2} - 14 u + 49

(3 d)^{- 3}

4 - 43 i

18 + 3 x^{2} - x = 0

1 - \frac{3}{5} (\frac{2}{3} + \frac{1}{2})

What are the solutions to the equation x^2+6x-27=0 ?
The solutions to the equation x^2+6x-27=0 are x=3,x=-9
Find the zeros of x^2+6x-27=0
The zeros of x^2+6x-27=0 are x=3,x=-9