What is 3 1/5 x+10 7/9-2 2/5 x-10 8/9 ?

The solution to 3 1/5 x+10 7/9-2 2/5 x-10 8/9 is (4x)/5-1/9

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simplify 3 1/5 x+10 7/9-2 2/5 x-10 8/9

simplify

3 \frac{1}{5} x + 10 \frac{7}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9}

\frac{4 x}{5} - \frac{1}{9}

Solution steps

3 \frac{1}{5} x + 10 \frac{7}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9}

Convert mixed numbers to improper fractions:

3 \frac{1}{5} = \frac{16}{5}

= \frac{16}{5} x + 10 \frac{7}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9}

Convert mixed numbers to improper fractions:

10 \frac{7}{9} = \frac{97}{9}

= \frac{16}{5} x + \frac{97}{9} - 2 \frac{2}{5} x - 10 \frac{8}{9}

Convert mixed numbers to improper fractions:

2 \frac{2}{5} = \frac{12}{5}

= \frac{16}{5} x + \frac{97}{9} - \frac{12}{5} x - 10 \frac{8}{9}

Convert mixed numbers to improper fractions:

10 \frac{8}{9} = \frac{98}{9}

= \frac{16}{5} x + \frac{97}{9} - \frac{12}{5} x - \frac{98}{9}

Factor out common term

x

= x (\frac{16}{5} - \frac{12}{5}) + \frac{97}{9} - \frac{98}{9}

\frac{16}{5} - \frac{12}{5} = \frac{4}{5}

= x \frac{4}{5} + \frac{97}{9} - \frac{98}{9}

Join

x \frac{4}{5} + \frac{97}{9} - \frac{98}{9} : \frac{4}{5} x + \frac{- 1}{9}

= \frac{4}{5} x + \frac{- 1}{9}

\frac{4}{5} x = \frac{4 x}{5}

\frac{- 1}{9} = - \frac{1}{9}

= \frac{4 x}{5} - \frac{1}{9}

f (- 10)

(x - 4) (2 x^{3} + 7 x^{2} - 5)

- \frac{1}{5}

2 \times 8

(a + b)^{1}

What is 3 1/5 x+10 7/9-2 2/5 x-10 8/9 ?
The solution to 3 1/5 x+10 7/9-2 2/5 x-10 8/9 is (4x)/5-1/9