What is (x^2-16)/(x^2+9x+20)*(x+5)/(x^2-7x+12) ?

The solution to (x^2-16)/(x^2+9x+20)*(x+5)/(x^2-7x+12) is 1/(x-3)

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simplify (x^2-16)/(x^2+9x+20)*(x+5)/(x^2-7x+12)

simplify

\frac{x ^{2} - 16}{x ^{2} + 9 x + 20} \cdot \frac{x + 5}{x ^{2} - 7 x + 12}

\frac{1}{x - 3}

Solution steps

\frac{x ^{2} - 16}{x ^{2} + 9 x + 20} \cdot \frac{x + 5}{x ^{2} - 7 x + 12}

Cancel

\frac{x ^{2} - 16}{x ^{2} + 9 x + 20} : \frac{x - 4}{x + 5}

= \frac{x - 4}{x + 5} \cdot \frac{x + 5}{x ^{2} - 7 x + 12}

Cross-cancel common factor:

x + 5

= \frac{x - 4}{x ^{2} - 7 x + 12}

Factor

x^{2} - 7 x + 12 : (x - 3) (x - 4)

= \frac{x - 4}{( x - 3 ) ( x - 4 )}

Cancel the common factor:

x - 4

= \frac{1}{x - 3}

(4^{5})^{3}

\frac{6 m ^{3} - 18 m ^{2} - 24 m}{15 m - 9 m ^{2}}

100 x^{2} - 49

6 (- 5 n + 7)

\frac{\frac{7 x}{x - 8}}{\frac{x ^{2} + 4 x - 32}{x ^{2} - 64}}

What is (x^2-16)/(x^2+9x+20)*(x+5)/(x^2-7x+12) ?
The solution to (x^2-16)/(x^2+9x+20)*(x+5)/(x^2-7x+12) is 1/(x-3)