What is p(p^{-7}q^3)^{-2}q^{-3} ?

The solution to p(p^{-7}q^3)^{-2}q^{-3} is (p^{15})/(q^9)

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simplify p(p^{-7}q^3)^{-2}q^{-3}

simplify

p (p^{- 7} q^{3})^{- 2} q^{- 3}

\frac{p ^{15}}{q ^{9}}

Solution steps

p (p^{- 7} q^{3})^{- 2} q^{- 3}

Simplify

(p^{- 7} q^{3})^{- 2} : \frac{p ^{14}}{q ^{6}}

= p \frac{p ^{14}}{q ^{6}} q^{- 3}

Apply exponent rule:

a^{- b} = \frac{1}{a ^{b}}

q^{- 3} = \frac{1}{q ^{3}}

= p \frac{p ^{14}}{q ^{6}} \cdot \frac{1}{q ^{3}}

Apply the fraction rule:

a \cdot \frac{b}{c} \cdot \frac{d}{e} = \frac{a \cdot b \cdot d}{c \cdot e}

= \frac{p p ^{14} \cdot 1}{q ^{6} q ^{3}}

Simplify

p p^{14} \cdot 1 : p^{15}

= \frac{p ^{15}}{q ^{6} q ^{3}}

Simplify

q^{6} q^{3} : q^{9}

= \frac{p ^{15}}{q ^{9}}

(x + 2) (x + 3) = 0

x^{5} - 21 x^{2} + 20 x

12 - 2 ∣ x + 4 ∣ > 6

x^{3} - 12 x^{2} + 47 x - 60

0 = x^{2} - 5 x + 4

What is p(p^{-7}q^3)^{-2}q^{-3} ?
The solution to p(p^{-7}q^3)^{-2}q^{-3} is (p^{15})/(q^9)