What are the solutions to the equation 4x^2+6x=8 ?

The solutions to the equation 4x^2+6x=8 are x=(-3+sqrt(41))/4 ,x=-(3+sqrt(41))/4

Find the zeros of 4x^2+6x=8

The zeros of 4x^2+6x=8 are x=(-3+sqrt(41))/4 ,x=-(3+sqrt(41))/4

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4 x^{2} + 6 x = 8

x = \frac{- 3 + 41}{4}, x = - \frac{3 + 41}{4}

Decimal Notation

x = 0.85078 \dots, x = - 2.35078 \dots

Solution steps

4 x^{2} + 6 x = 8

Move

8

to the left side

4 x^{2} + 6 x - 8 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 6 \pm 6 ^{2} - 4 \cdot 4 ( - 8 )}{2 \cdot 4}

6^{2} - 4 \cdot 4 (- 8) = 241

x_{1, 2} = \frac{- 6 \pm 2 41}{2 \cdot 4}

Separate the solutions

x_{1} = \frac{- 6 + 2 41}{2 \cdot 4}, x_{2} = \frac{- 6 - 2 41}{2 \cdot 4}

x = \frac{- 6 + 2 41}{2 \cdot 4} : \frac{- 3 + 41}{4}

x = \frac{- 6 - 2 41}{2 \cdot 4} : - \frac{3 + 41}{4}

The solutions to the quadratic equation are:

x = \frac{- 3 + 41}{4}, x = - \frac{3 + 41}{4}

\frac{5 x}{6} - \frac{7}{4} + \frac{2 x}{3} = 2 x - \frac{5}{12} + \frac{x}{3}

w^{2} + 3 w = 40

6 v^{2} + 42 v + 72

- 7 d^{2} + 2 d + 9 = 0

108

What are the solutions to the equation 4x^2+6x=8 ?
The solutions to the equation 4x^2+6x=8 are x=(-3+sqrt(41))/4 ,x=-(3+sqrt(41))/4
Find the zeros of 4x^2+6x=8
The zeros of 4x^2+6x=8 are x=(-3+sqrt(41))/4 ,x=-(3+sqrt(41))/4