What are the solutions to the equation 3x^2+x+7=0 ?

The solutions to the equation 3x^2+x+7=0 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6

Find the zeros of 3x^2+x+7=0

The zeros of 3x^2+x+7=0 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6

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3 x^{2} + x + 7 = 0

x = - \frac{1}{6} + i \frac{83}{6}, x = - \frac{1}{6} - i \frac{83}{6}

Solution steps

3 x^{2} + x + 7 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 1 \pm 1 ^{2} - 4 \cdot 3 \cdot 7}{2 \cdot 3}

Simplify

1^{2} - 4 \cdot 3 \cdot 7 : 83 i

x_{1, 2} = \frac{- 1 \pm 83 i}{2 \cdot 3}

Separate the solutions

x_{1} = \frac{- 1 + 83 i}{2 \cdot 3}, x_{2} = \frac{- 1 - 83 i}{2 \cdot 3}

x = \frac{- 1 + 83 i}{2 \cdot 3} : - \frac{1}{6} + i \frac{83}{6}

x = \frac{- 1 - 83 i}{2 \cdot 3} : - \frac{1}{6} - i \frac{83}{6}

The solutions to the quadratic equation are:

x = - \frac{1}{6} + i \frac{83}{6}, x = - \frac{1}{6} - i \frac{83}{6}

6 (- 3 x + 1) = - 17 (x + 1)

\frac{\frac{k ^{2}}{4} - 9}{\frac{k}{6} - 1}

x + 4 = 25

- 150 x^{2} + 1.2 x + (- 380) = 0

2 (x - 4)^{2} = 12

What are the solutions to the equation 3x^2+x+7=0 ?
The solutions to the equation 3x^2+x+7=0 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6
Find the zeros of 3x^2+x+7=0
The zeros of 3x^2+x+7=0 are x=-1/6+i(sqrt(83))/6 ,x=-1/6-i(sqrt(83))/6