What are the solutions to the equation 2(x-4)^2=12 ?

The solutions to the equation 2(x-4)^2=12 are x=sqrt(6)+4,x=-sqrt(6)+4

Find the zeros of 2(x-4)^2=12

The zeros of 2(x-4)^2=12 are x=sqrt(6)+4,x=-sqrt(6)+4

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2 (x - 4)^{2} = 12

x = 6 + 4, x = - 6 + 4

Decimal Notation

x = 6.44948 \dots, x = 1.55051 \dots

Solution steps

2 (x - 4)^{2} = 12

Divide both sides by

2

(x - 4)^{2} = 6

For

(g (x))^{2} = f (a)

the solutions are

g (x) = f (a), - f (a)

Solve

x - 4 = 6 : x = 6 + 4

Solve

x - 4 = - 6 : x = - 6 + 4

The solutions to the quadratic equation are:

x = 6 + 4, x = - 6 + 4

- (x - 2) + 2 (3 + x) = 3 (x + 4)

12 x^{2} - 6 x + 1 = 0

3 h^{2} + 10 h + 3

2 (- 1) + 3

10 w + 4 w = - 84

What are the solutions to the equation 2(x-4)^2=12 ?
The solutions to the equation 2(x-4)^2=12 are x=sqrt(6)+4,x=-sqrt(6)+4
Find the zeros of 2(x-4)^2=12
The zeros of 2(x-4)^2=12 are x=sqrt(6)+4,x=-sqrt(6)+4