What is (-36k^5m^8n^3)/(12k^7m^{10)n^5} ?

The solution to (-36k^5m^8n^3)/(12k^7m^{10)n^5} is -3/(k^2m^2n^2)

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simplify (-36k^5m^8n^3)/(12k^7m^{10)n^5}

simplify

\frac{- 36 k ^{5} m ^{8} n ^{3}}{12 k ^{7} m ^{10} n ^{5}}

- \frac{3}{k ^{2} m ^{2} n ^{2}}

Solution steps

\frac{- 36 k ^{5} m ^{8} n ^{3}}{12 k ^{7} m ^{10} n ^{5}}

Factor the number:

36 = 12 \cdot 3

= \frac{- 12 \cdot 3 k ^{5} m ^{8} n ^{3}}{12 k ^{7} m ^{10} n ^{5}}

Cancel the common factor:

12

= \frac{- 3 k ^{5} m ^{8} n ^{3}}{k ^{7} m ^{10} n ^{5}}

Simplify

\frac{k ^{5}}{k ^{7}} : \frac{1}{k ^{2}}

= \frac{- 3 m ^{8} n ^{3}}{k ^{2} m ^{10} n ^{5}}

Simplify

\frac{m ^{8}}{m ^{10}} : \frac{1}{m ^{2}}

= \frac{- 3 n ^{3}}{k ^{2} m ^{2} n ^{5}}

Simplify

\frac{n ^{3}}{n ^{5}} : \frac{1}{n ^{2}}

= \frac{- 3}{k ^{2} m ^{2} n ^{2}}

Apply the fraction rule:

\frac{- a}{b} = - \frac{a}{b}

= - \frac{3}{k ^{2} m ^{2} n ^{2}}

6 (2 x - 3) - 2 (2 x + 1)

\frac{( 2 y ) ^{3}}{( x ^{3} y ^{4} ) ^{3} \cdot ( 2 x y ^{- 4} ) ^{- 3}}

lo g_{\frac{1}{6}} (x)

\frac{90}{60}

\frac{1}{4 ( \frac{1}{4 x} )}

What is (-36k^5m^8n^3)/(12k^7m^{10)n^5} ?
The solution to (-36k^5m^8n^3)/(12k^7m^{10)n^5} is -3/(k^2m^2n^2)