What is (y^2-16)/(2y+6)*(y+3)/(y-4) ?

The solution to (y^2-16)/(2y+6)*(y+3)/(y-4) is (y+4)/2

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simplify (y^2-16)/(2y+6)*(y+3)/(y-4)

simplify

\frac{y ^{2} - 16}{2 y + 6} \cdot \frac{y + 3}{y - 4}

\frac{y + 4}{2}

Solution steps

\frac{y ^{2} - 16}{2 y + 6} \cdot \frac{y + 3}{y - 4}

Apply the fraction rule:

\frac{a}{b} \cdot \frac{c}{d} = \frac{a \cdot c}{b \cdot d}

= \frac{( y ^{2} - 16 ) ( y + 3 )}{( 2 y + 6 ) ( y - 4 )}

Factor

y^{2} - 16 : (y + 4) (y - 4)

= \frac{( y + 4 ) ( y - 4 ) ( y + 3 )}{( 2 y + 6 ) ( y - 4 )}

Cancel the common factor:

y - 4

= \frac{( y + 4 ) ( y + 3 )}{2 y + 6}

Factor

2 y + 6 : 2 (y + 3)

= \frac{( y + 4 ) ( y + 3 )}{2 ( y + 3 )}

Cancel the common factor:

y + 3

= \frac{y + 4}{2}

(7 a^{4})^{2}

(32 x^{30} y^{- 40})^{- \frac{2}{5}}

lo g_{8} (512) + lo g_{512} (8)

\frac{12 x + 36}{x ^{2} - 4 x - 21}

\frac{1}{2} \cdot \frac{2}{6}

What is (y^2-16)/(2y+6)*(y+3)/(y-4) ?
The solution to (y^2-16)/(2y+6)*(y+3)/(y-4) is (y+4)/2