What is (2^4+2^{-4})/(4^4+1) ?

The solution to (2^4+2^{-4})/(4^4+1) is 1/16

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simplify (2^4+2^{-4})/(4^4+1)

simplify

\frac{2 ^{4} + 2 ^{- 4}}{4 ^{4} + 1}

\frac{1}{16}

Decimal Notation

0.0625

Solution steps

\frac{2 ^{4} + 2 ^{- 4}}{4 ^{4} + 1}

Simplify

2^{4} + 2^{- 4} : \frac{257}{16}

= \frac{\frac{257}{16}}{4 ^{4} + 1}

4^{4} + 1 = 257

= \frac{\frac{257}{16}}{257}

Apply the fraction rule:

\frac{\frac{a}{b}}{c} = \frac{a}{b \cdot c}

= \frac{257}{16 \cdot 257}

Cancel the common factor:

257

= \frac{1}{16}

- 12 (- 4 - 2)

\frac{\frac{x + 8}{x ^{2} - 64}}{\frac{x - 4}{x ^{2} + x - 72}}

7 ab + 4 ab - 3 ab

(7 i) (- 3 i)