What is factor 3x^3+4x^2+6x+5 ?

The solution to factor 3x^3+4x^2+6x+5 is (x+1)(3x^2+x+5)

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factor 3x^3+4x^2+6x+5

factor

3 x^{3} + 4 x^{2} + 6 x + 5

(x + 1) (3 x^{2} + x + 5)

Solution steps

3 x^{3} + 4 x^{2} + 6 x + 5

Use the rational root theorem

= (x + 1) \frac{3 x ^{3} + 4 x ^{2} + 6 x + 5}{x + 1}

\frac{3 x ^{3} + 4 x ^{2} + 6 x + 5}{x + 1} = 3 x^{2} + x + 5

= (x + 1) (3 x^{2} + x + 5)

(3 x - 4) (2 x - 3)

\frac{2}{3} + \frac{4}{6}

(x + 3) (2 x - 4)

- 5 x y^{2} (- 8 x^{5} y)

f (n) = \frac{4 n + 24}{n ^{2} - 2 n - 48}

What is factor 3x^3+4x^2+6x+5 ?
The solution to factor 3x^3+4x^2+6x+5 is (x+1)(3x^2+x+5)