What is (2x^2-3x+1)/(2x^2+x-1) ?

The solution to (2x^2-3x+1)/(2x^2+x-1) is (x-1)/(x+1)

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simplify (2x^2-3x+1)/(2x^2+x-1)

simplify

\frac{2 x ^{2} - 3 x + 1}{2 x ^{2} + x - 1}

\frac{x - 1}{x + 1}

Solution steps

\frac{2 x ^{2} - 3 x + 1}{2 x ^{2} + x - 1}

Factor

2 x^{2} - 3 x + 1 : (2 x - 1) (x - 1)

= \frac{( 2 x - 1 ) ( x - 1 )}{2 x ^{2} + x - 1}

Factor

2 x^{2} + x - 1 : (2 x - 1) (x + 1)

= \frac{( 2 x - 1 ) ( x - 1 )}{( 2 x - 1 ) ( x + 1 )}

Cancel the common factor:

2 x - 1

= \frac{x - 1}{x + 1}

\frac{x ^{2} + 17 x + 70}{x ^{2} + 6 x - 40}

49 d^{2} n - 25 n

∣ 6 - 8 i ∣

(t - 3)^{3}

- x^{2} + 2 x^{2}

What is (2x^2-3x+1)/(2x^2+x-1) ?
The solution to (2x^2-3x+1)/(2x^2+x-1) is (x-1)/(x+1)