What is (-2a^2+a+6)-(-3a^2+2a-5) ?

The solution to (-2a^2+a+6)-(-3a^2+2a-5) is a^2-a+11

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simplify (-2a^2+a+6)-(-3a^2+2a-5)

simplify

(- 2 a^{2} + a + 6) - (- 3 a^{2} + 2 a - 5)

a^{2} - a + 11

Solution steps

(- 2 a^{2} + a + 6) - (- 3 a^{2} + 2 a - 5)

Apply rule:

(a) = a

(- 2 a^{2} + a + 6) = - 2 a^{2} + a + 6

= - 2 a^{2} + a + 6 - (- 3 a^{2} + 2 a - 5)

Apply the distributive law:

- (- a + b) = a - b

- (- 3 a^{2} + 2 a - 5) = 3 a^{2} - 2 a + 5

= - 2 a^{2} + a + 6 + 3 a^{2} - 2 a + 5

Group like terms

= - 2 a^{2} + 3 a^{2} + a - 2 a + 6 + 5

Add similar elements:

- 2 a^{2} + 3 a^{2} = a^{2}

= a^{2} + a - 2 a + 6 + 5

Add similar elements:

a - 2 a = - a

= a^{2} - a + 6 + 5

Add the numbers:

6 + 5 = 11

= a^{2} - a + 11

\frac{3 x ^{2} + 3 x - 6}{6 ( x ^{2} - 2 x + 1 )}

\frac{1}{i} + \frac{3 + 2 i}{2 - i}

x^{- a}

\frac{- \frac{4}{5}}{- \frac{3}{5}}

- \frac{4}{- 8}

What is (-2a^2+a+6)-(-3a^2+2a-5) ?
The solution to (-2a^2+a+6)-(-3a^2+2a-5) is a^2-a+11