What is ((x^3+3x^2+3x+1))/((x+1)) ?

The solution to ((x^3+3x^2+3x+1))/((x+1)) is (x+1)^2

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simplify ((x^3+3x^2+3x+1))/((x+1))

simplify

\frac{( x ^{3} + 3 x ^{2} + 3 x + 1 )}{( x + 1 )}

(x + 1)^{2}

Solution steps

\frac{x ^{3} + 3 x ^{2} + 3 x + 1}{x + 1}

Apply cube of sum rule:

x^{3} + 3 x^{2} y + 3 x y^{2} + y^{3} = (x + y)^{3}

x^{3} + 3 x^{2} + 3 x + 1 = (x + 1)^{3}

= \frac{( x + 1 ) ^{3}}{x + 1}

Apply exponent rule:

a^{b + c} = a^{b} \cdot a^{c}

(x + 1)^{3} = (x + 1) (x + 1)^{2}

= \frac{( x + 1 ) ( x + 1 ) ^{2}}{x + 1}

Cancel the common factor:

x + 1

= (x + 1)^{2}

(x^{2} - 4 x + 4) (x - 2)

\frac{3}{5} \div \frac{1}{9}

\frac{1}{2 x ^{2} + 11 x + 15} + \frac{6 x + 7}{3 x ^{2} + 7 x - 6} - \frac{19}{6 x ^{2} + 11 x - 10}

(4 + 6 i) - (- 1 + 2 i)

\frac{1}{3 ( 125 ) ^{\frac{2}{3}}}

What is ((x^3+3x^2+3x+1))/((x+1)) ?
The solution to ((x^3+3x^2+3x+1))/((x+1)) is (x+1)^2