What are the solutions to the equation 4x^2+8x+4=0 ?

The solutions to the equation 4x^2+8x+4=0 are x=-1

Find the zeros of 4x^2+8x+4=0

The zeros of 4x^2+8x+4=0 are x=-1

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4 x^{2} + 8 x + 4 = 0

x = - 1

Solution steps

4 x^{2} + 8 x + 4 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 8 \pm 8 ^{2} - 4 \cdot 4 \cdot 4}{2 \cdot 4}

8^{2} - 4 \cdot 4 \cdot 4 = 0

x_{1, 2} = \frac{- 8 \pm 0}{2 \cdot 4}

x = \frac{- 8}{2 \cdot 4}

\frac{- 8}{2 \cdot 4} = - 1

x = - 1

The solution to the quadratic equation is:

x = - 1

∣ x + 2 ∣ \leq 7

2 x + 8 > 12

5 x^{2} = 6 x

\frac{14}{7}

3 x^{2} + 6 x = 12

What are the solutions to the equation 4x^2+8x+4=0 ?
The solutions to the equation 4x^2+8x+4=0 are x=-1
Find the zeros of 4x^2+8x+4=0
The zeros of 4x^2+8x+4=0 are x=-1