What is (\frac{21m^7)/(8n^3)}{(7m^8)/(12n^4)} ?

The solution to (\frac{21m^7)/(8n^3)}{(7m^8)/(12n^4)} is (9n)/(2m)

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simplify (\frac{21m^7)/(8n^3)}{(7m^8)/(12n^4)}

simplify

\frac{\frac{21 m ^{7}}{8 n ^{3}}}{\frac{7 m ^{8}}{12 n ^{4}}}

\frac{9 n}{2 m}

Solution steps

\frac{\frac{21 m ^{7}}{8 n ^{3}}}{\frac{7 m ^{8}}{12 n ^{4}}}

Apply the fraction rule:

\frac{\frac{a}{b}}{\frac{c}{d}} = \frac{a \cdot d}{b \cdot c}

= \frac{21 m ^{7} \cdot 12 n ^{4}}{8 n ^{3} \cdot 7 m ^{8}}

Cancel

\frac{21 m ^{7} \cdot 12 n ^{4}}{8 n ^{3} \cdot 7 m ^{8}} : \frac{9 n}{2 m}

= \frac{9 n}{2 m}

- i^{5}

\frac{x + 2}{3 x} + \frac{x ^{2} - 2}{5 x ^{2}} + \frac{2 - x ^{3}}{9 x ^{3}}

1.5 \times 3

⌊ 0.5 ⌋

x - 4^{2}

What is (\frac{21m^7)/(8n^3)}{(7m^8)/(12n^4)} ?
The solution to (\frac{21m^7)/(8n^3)}{(7m^8)/(12n^4)} is (9n)/(2m)