What is 1/(2x^2-4x)-2/x ?

The solution to 1/(2x^2-4x)-2/x is (-4x+9)/(2x(x-2))

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simplify 1/(2x^2-4x)-2/x

simplify

\frac{1}{2 x ^{2} - 4 x} - \frac{2}{x}

\frac{- 4 x + 9}{2 x ( x - 2 )}

Solution steps

\frac{1}{2 x ^{2} - 4 x} - \frac{2}{x}

Least Common Multiplier of

2 x^{2} - 4 x, x : 2 x (x - 2)

Adjust Fractions based on the LCM

= \frac{1}{2 x ( x - 2 )} - \frac{4 ( x - 2 )}{2 x ( x - 2 )}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{1 - 4 ( x - 2 )}{2 x ( x - 2 )}

Simplify

1 - 4 (x - 2) : - 4 x + 9

= \frac{- 4 x + 9}{2 x ( x - 2 )}

\frac{( 4 s ^{- 1} j ^{- 3} ) ^{- 3}}{20 s ^{- 2}}

lo g_{6} (30) - lo g_{6} (5)

x^{2} (x + 1)^{3}

- 5 - 9

(11 - 12 i) - (10 + 9 i)