What is expand (8x^3-9y^3+6xy^2-12x^2y)(2x+3y) ?

The solution to expand (8x^3-9y^3+6xy^2-12x^2y)(2x+3y) is 16x^4-27y^4-24x^2y^2

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expand (8x^3-9y^3+6xy^2-12x^2y)(2x+3y)

expand

(8 x^{3} - 9 y^{3} + 6 x y^{2} - 12 x^{2} y) (2 x + 3 y)

16 x^{4} - 27 y^{4} - 24 x^{2} y^{2}

Solution steps

(8 x^{3} - 9 y^{3} + 6 x y^{2} - 12 x^{2} y) (2 x + 3 y)

Distribute parentheses

= 8 x^{3} \cdot 2 x + 8 x^{3} \cdot 3 y - 9 y^{3} \cdot 2 x - 9 y^{3} \cdot 3 y + 6 x y^{2} \cdot 2 x + 6 x y^{2} \cdot 3 y - 12 x^{2} y \cdot 2 x - 12 x^{2} y \cdot 3 y

Simplify

8 x^{3} \cdot 2 x + 8 x^{3} \cdot 3 y - 9 y^{3} \cdot 2 x - 9 y^{3} \cdot 3 y + 6 x y^{2} \cdot 2 x + 6 x y^{2} \cdot 3 y - 12 x^{2} y \cdot 2 x - 12 x^{2} y \cdot 3 y : 16 x^{4} - 27 y^{4} - 24 x^{2} y^{2}

= 16 x^{4} - 27 y^{4} - 24 x^{2} y^{2}

2 x \times (- 1)

\frac{( 2 x ^{2} + x - 3 )}{( x - 1 )}

lo g_{3} (3^{\frac{1}{4}})

(4 x + 7) (x - 2) (x - 1) (x - 1)

- a^{2} b - a^{2} b - 3 a^{2} b

What is expand (8x^3-9y^3+6xy^2-12x^2y)(2x+3y) ?
The solution to expand (8x^3-9y^3+6xy^2-12x^2y)(2x+3y) is 16x^4-27y^4-24x^2y^2