What is (b^2-11b+28)/(b^2-6b-7)-1/(b+1) ?

The solution to (b^2-11b+28)/(b^2-6b-7)-1/(b+1) is (b-5)/(b+1)

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simplify (b^2-11b+28)/(b^2-6b-7)-1/(b+1)

simplify

\frac{b ^{2} - 11 b + 28}{b ^{2} - 6 b - 7} - \frac{1}{b + 1}

\frac{b - 5}{b + 1}

Solution steps

\frac{b ^{2} - 11 b + 28}{b ^{2} - 6 b - 7} - \frac{1}{b + 1}

Cancel

\frac{b ^{2} - 11 b + 28}{b ^{2} - 6 b - 7} : \frac{b - 4}{b + 1}

= \frac{b - 4}{b + 1} - \frac{1}{b + 1}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{b - 4 - 1}{b + 1}

Subtract the numbers:

- 4 - 1 = - 5

= \frac{b - 5}{b + 1}

\frac{1}{16} \cdot 64

9 n^{2} - 30 n - 18 n^{4}

1 0^{- 3.2}

(e^{\frac{x}{2}})^{2}

x^{2} + 4 = 4

What is (b^2-11b+28)/(b^2-6b-7)-1/(b+1) ?
The solution to (b^2-11b+28)/(b^2-6b-7)-1/(b+1) is (b-5)/(b+1)