What is factor x^4-x^3-5x^2-x-6 ?

The solution to factor x^4-x^3-5x^2-x-6 is (x+2)(x-3)(x^2+1)

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factor x^4-x^3-5x^2-x-6

factor

x^{4} - x^{3} - 5 x^{2} - x - 6

(x + 2) (x - 3) (x^{2} + 1)

Solution steps

x^{4} - x^{3} - 5 x^{2} - x - 6

Use the rational root theorem

= (x + 2) \frac{x ^{4} - x ^{3} - 5 x ^{2} - x - 6}{x + 2}

\frac{x ^{4} - x ^{3} - 5 x ^{2} - x - 6}{x + 2} = x^{3} - 3 x^{2} + x - 3

= (x + 2) (x^{3} - 3 x^{2} + x - 3)

Factor

x^{3} - 3 x^{2} + x - 3 : (x - 3) (x^{2} + 1)

= (x + 2) (x - 3) (x^{2} + 1)

\frac{\frac{4 p - 4}{p}}{\frac{9 p - 9}{4 p ^{2}}}

\frac{2 x ^{- 1} - 3 x ^{- 2}}{4 x ^{- 3}}

(2 x - 5)^{4}

4^{- 1.5}

4 m - 3 + 2 m + 5

What is factor x^4-x^3-5x^2-x-6 ?
The solution to factor x^4-x^3-5x^2-x-6 is (x+2)(x-3)(x^2+1)