What is factor 2x^3+9x^2+7x-6 ?

The solution to factor 2x^3+9x^2+7x-6 is (2x-1)(x+2)(x+3)

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factor 2x^3+9x^2+7x-6

factor

2 x^{3} + 9 x^{2} + 7 x - 6

(2 x - 1) (x + 2) (x + 3)

Solution steps

2 x^{3} + 9 x^{2} + 7 x - 6

Use the rational root theorem

= (2 x - 1) \frac{2 x ^{3} + 9 x ^{2} + 7 x - 6}{2 x - 1}

\frac{2 x ^{3} + 9 x ^{2} + 7 x - 6}{2 x - 1} = x^{2} + 5 x + 6

= (2 x - 1) (x^{2} + 5 x + 6)

Factor

x^{2} + 5 x + 6 : (x + 2) (x + 3)

= (2 x - 1) (x + 2) (x + 3)

\frac{4 x ^{2}}{3 y}

3 x^{1}

\frac{32 p ^{5} q ^{6}}{- 8 p ^{3} q ^{2}}

(x - 4 y)^{3}

(33)^{3}

What is factor 2x^3+9x^2+7x-6 ?
The solution to factor 2x^3+9x^2+7x-6 is (2x-1)(x+2)(x+3)