What is expand 1/2 (3-x)(2-x) ?

The solution to expand 1/2 (3-x)(2-x) is 3-(5x)/2+(x^2)/2

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expand 1/2 (3-x)(2-x)

expand

\frac{1}{2} (3 - x) (2 - x)

3 - \frac{5 x}{2} + \frac{x ^{2}}{2}

Solution steps

\frac{1}{2} (3 - x) (2 - x)

Expand

\frac{1}{2} (3 - x) (2 - x) : \frac{1}{2} (6 - 5 x + x^{2})

= \frac{1}{2} (6 - 5 x + x^{2})

Apply the distributive law:

m (a + b + c) = ma + mb + m c

\frac{1}{2} (6 - 5 x + x^{2}) = \frac{1}{2} \cdot 6 + \frac{1}{2} (- 5 x) + \frac{1}{2} x^{2}

= \frac{1}{2} \cdot 6 + \frac{1}{2} (- 5 x) + \frac{1}{2} x^{2}

Simplify

\frac{1}{2} \cdot 6 + \frac{1}{2} (- 5 x) + \frac{1}{2} x^{2} : 3 - \frac{5 x}{2} + \frac{x ^{2}}{2}

= 3 - \frac{5 x}{2} + \frac{x ^{2}}{2}

(r sin (θ))^{2}

\frac{3 + 7}{2 - 10}

2.8

(9 x + 2 y)^{2}

\frac{x ^{2} - 4}{x ^{3} - 8}

What is expand 1/2 (3-x)(2-x) ?
The solution to expand 1/2 (3-x)(2-x) is 3-(5x)/2+(x^2)/2