What is 2/(3x^2-10x-8)+1/(x-4) ?

The solution to 2/(3x^2-10x-8)+1/(x-4) is (3x+4)/((x-4)(3x+2))

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simplify 2/(3x^2-10x-8)+1/(x-4)

simplify

\frac{2}{3 x ^{2} - 10 x - 8} + \frac{1}{x - 4}

\frac{3 x + 4}{( x - 4 ) ( 3 x + 2 )}

Solution steps

\frac{2}{3 x ^{2} - 10 x - 8} + \frac{1}{x - 4}

Least Common Multiplier of

3 x^{2} - 10 x - 8, x - 4 : (x - 4) (3 x + 2)

Adjust Fractions based on the LCM

= \frac{2}{( x - 4 ) ( 3 x + 2 )} + \frac{3 x + 2}{( x - 4 ) ( 3 x + 2 )}

Apply the fraction rule:

\frac{a}{c} + \frac{b}{c} = \frac{a + b}{c}

= \frac{2 + 3 x + 2}{( x - 4 ) ( 3 x + 2 )}

Simplify

2 + 3 x + 2 : 3 x + 4

= \frac{3 x + 4}{( x - 4 ) ( 3 x + 2 )}

2 x \times 3

\frac{3 x + 2}{x + 6} - x

(1 - 2 x)^{5}

60 \div 15

2 lo g_{2} (32) + lo g_{4} (256) + 3 lo g_{3} (81)

What is 2/(3x^2-10x-8)+1/(x-4) ?
The solution to 2/(3x^2-10x-8)+1/(x-4) is (3x+4)/((x-4)(3x+2))