What is 2log_{2}(32)+log_{4}(256)+3log_{3}(81) ?

The solution to 2log_{2}(32)+log_{4}(256)+3log_{3}(81) is 26

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simplify 2log_{2}(32)+log_{4}(256)+3log_{3}(81)

simplify

2 lo g_{2} (32) + lo g_{4} (256) + 3 lo g_{3} (81)

26

Solution steps

2 lo g_{2} (32) + lo g_{4} (256) + 3 lo g_{3} (81)

2 lo g_{2} (32) = 10

lo g_{4} (256) = 4

3 lo g_{3} (81) = 12

= 10 + 4 + 12

Add the numbers:

10 + 4 + 12 = 26

= 26

(4 - 3 i) (- 3 + 6 i) - (2 - i)

(a + 7) (a - 7)

5 (a^{5} b^{4} - 3 a^{4} b^{3} - 8 a^{3} b^{2})

225 a^{2} - 144 b^{2}

(0.2)^{5}

What is 2log_{2}(32)+log_{4}(256)+3log_{3}(81) ?
The solution to 2log_{2}(32)+log_{4}(256)+3log_{3}(81) is 26