What is (-a^m)(-2ab)(-3a^2b^x) ?

The solution to (-a^m)(-2ab)(-3a^2b^x) is -6a^{m+3}b^{1+x}

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simplify (-a^m)(-2ab)(-3a^2b^x)

simplify

(- a^{m}) (- 2 ab) (- 3 a^{2} b^{x})

- 6 a^{m + 3} b^{1 + x}

Solution steps

(- a^{m}) (- 2 ab) (- 3 a^{2} b^{x})

Simplify

(- a^{m}) (- 2 ab) (- 3 a^{2} b^{x}) : - 2 a^{m + 1} b (3 a^{2} b^{x})

= - 2 a^{m + 1} b \cdot 3 a^{2} b^{x}

Multiply the numbers:

- 2 \cdot 3 = - 6

= - 6 a^{m + 1} b a^{2} b^{x}

Simplify

a^{m + 1} a^{2} : a^{m + 3}

= - 6 a^{m + 3} b b^{x}

Apply exponent rule:

a^{b} \cdot a^{c} = a^{b + c}

b b^{x} = b^{1 + x}

= - 6 a^{m + 3} b^{1 + x}

\frac{2 v ^{2} + 10 v - 48}{8 v + 64}

(a + 4) (a - 5)

(x^{3}) (- 9 x)

81 + - 6 - 64 + - 150

(a^{2} \cdot a^{2} \cdot a^{2})^{3}

What is (-a^m)(-2ab)(-3a^2b^x) ?
The solution to (-a^m)(-2ab)(-3a^2b^x) is -6a^{m+3}b^{1+x}