What are the solutions to the equation 3g^2-63=20g ?

The solutions to the equation 3g^2-63=20g are g=9,g=-7/3

Find the zeros of 3g^2-63=20g

The zeros of 3g^2-63=20g are g=9,g=-7/3

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3 g^{2} - 63 = 20 g

g = 9, g = - \frac{7}{3}

Solution steps

3 g^{2} - 63 = 20 g

Move

20 g

to the left side

3 g^{2} - 63 - 20 g = 0

Write in the standard form

a x^{2} + b x + c = 0

3 g^{2} - 20 g - 63 = 0

Solve with the quadratic formula

g_{1, 2} = \frac{- ( - 20 ) \pm ( - 20 ) ^{2} - 4 \cdot 3 ( - 63 )}{2 \cdot 3}

(- 20)^{2} - 4 \cdot 3 (- 63) = 34

g_{1, 2} = \frac{- ( - 20 ) \pm 34}{2 \cdot 3}

Separate the solutions

g_{1} = \frac{- ( - 20 ) + 34}{2 \cdot 3}, g_{2} = \frac{- ( - 20 ) - 34}{2 \cdot 3}

g = \frac{- ( - 20 ) + 34}{2 \cdot 3} : 9

g = \frac{- ( - 20 ) - 34}{2 \cdot 3} : - \frac{7}{3}

The solutions to the quadratic equation are:

g = 9, g = - \frac{7}{3}

3 = x - 3 x^{2}

lo g_{6} (4)

8 - ∣ 2 x + 9 ∣ \leq 5

\frac{3 x}{7} + \frac{2}{7} = 2

(x - 2) (x + 2) = 0

What are the solutions to the equation 3g^2-63=20g ?
The solutions to the equation 3g^2-63=20g are g=9,g=-7/3
Find the zeros of 3g^2-63=20g
The zeros of 3g^2-63=20g are g=9,g=-7/3