What is (16x-12)/(4x^2+5x-6)-3/(x+2) ?

The solution to (16x-12)/(4x^2+5x-6)-3/(x+2) is 1/(x+2)

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simplify (16x-12)/(4x^2+5x-6)-3/(x+2)

simplify

\frac{16 x - 12}{4 x ^{2} + 5 x - 6} - \frac{3}{x + 2}

\frac{1}{x + 2}

Solution steps

\frac{16 x - 12}{4 x ^{2} + 5 x - 6} - \frac{3}{x + 2}

Cancel

\frac{16 x - 12}{4 x ^{2} + 5 x - 6} : \frac{4}{x + 2}

= \frac{4}{x + 2} - \frac{3}{x + 2}

Apply the fraction rule:

\frac{a}{c} - \frac{b}{c} = \frac{a - b}{c}

= \frac{4 - 3}{x + 2}

Subtract the numbers:

4 - 3 = 1

= \frac{1}{x + 2}

\frac{5}{- 6}

2 \frac{7}{10}

- 2 x^{4} + 20 x^{3} + 48 x^{2}

(3 c - 4) (2 c^{2} - 5 c + 7)

What is (16x-12)/(4x^2+5x-6)-3/(x+2) ?
The solution to (16x-12)/(4x^2+5x-6)-3/(x+2) is 1/(x+2)