What is factor 1+27s^3 ?

The solution to factor 1+27s^3 is (3s+1)(9s^2-3s+1)

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factor 1+27s^3

factor

1 + 27 s^{3}

(3 s + 1) (9 s^{2} - 3 s + 1)

Solution steps

1 + 27 s^{3}

Write in the standard form

= 27 s^{3} + 1

Apply exponent rules

= (3 s)^{3} + 1^{3}

Apply Sum of Cubes Formula:

x^{3} + y^{3} = (x + y) (x^{2} - x y + y^{2})

(3 s)^{3} + 1^{3} = (3 s + 1) (3^{2} s^{2} - 3 s + 1)

= (3 s + 1) (3^{2} s^{2} - 3 s + 1)

3^{2} = 9

= (3 s + 1) (9 s^{2} - 3 s + 1)

45 \times 5

45 \times 3

\frac{5}{5}

\frac{3 x ^{3} + 4 x ^{2} - 5 x - 2}{x + 2}

\frac{5}{6} - \frac{6}{5}