What is expand (3x-1)(4x+3)(x+1) ?

The solution to expand (3x-1)(4x+3)(x+1) is 12x^3+17x^2+2x-3

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expand (3x-1)(4x+3)(x+1)

expand

(3 x - 1) (4 x + 3) (x + 1)

12 x^{3} + 17 x^{2} + 2 x - 3

Solution steps

(3 x - 1) (4 x + 3) (x + 1)

Expand

(3 x - 1) (4 x + 3) (x + 1) : (12 x^{2} + 5 x - 3) (x + 1)

= (12 x^{2} + 5 x - 3) (x + 1)

Distribute parentheses

= 12 x^{2} x + 12 x^{2} \cdot 1 + 5 xx + 5 x \cdot 1 - 3 x - 3 \cdot 1

Simplify

12 x^{2} x + 12 x^{2} \cdot 1 + 5 xx + 5 x \cdot 1 - 3 x - 3 \cdot 1 : 12 x^{3} + 17 x^{2} + 2 x - 3

= 12 x^{3} + 17 x^{2} + 2 x - 3

x^{3} - 7 x^{2} - 6 x + 42

x^{4} y - x^{2}

ln (\frac{1}{1})

\frac{2 x ^{3} + 16 x ^{2} + 24 x}{x ^{2} - x - 6}

\frac{17 x ^{3} y ^{4} z ^{6}}{34 x ^{7} y ^{8} z ^{10}}

What is expand (3x-1)(4x+3)(x+1) ?
The solution to expand (3x-1)(4x+3)(x+1) is 12x^3+17x^2+2x-3