What is 1/(sin^2(x))+(sec^2(x))/(tan^2(x)) ?

The solution to 1/(sin^2(x))+(sec^2(x))/(tan^2(x)) is 2csc^2(x)

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simplify 1/(sin^2(x))+(sec^2(x))/(tan^2(x))

simplify

\frac{1}{sin ^{2} ( x )} + \frac{sec ^{2} ( x )}{tan ^{2} ( x )}

2 csc^{2} (x)

Solution steps

\frac{1}{sin ^{2} ( x )} + \frac{sec ^{2} ( x )}{tan ^{2} ( x )}

Join

\frac{1}{sin ^{2} ( x )} + \frac{sec ^{2} ( x )}{tan ^{2} ( x )} : 2 csc^{2} (x)

= 2 csc^{2} (x)

(x - 0) (x - 1) (x - 4)

6 a^{8} + 12 a^{6} - 18 a^{4} + 24 a^{2}

\frac{x ^{2} + x - 6}{x ^{2} - 5 x + 6} \cdot \frac{x ^{2} - 2 x - 3}{x ^{2} - 4 x - 5}

\frac{4 x - 16}{x} \cdot \frac{x ^{2} - 11 x + 24}{x ^{2} - 7 x + 12}

lo g_{4} (1 6^{5})

What is 1/(sin^2(x))+(sec^2(x))/(tan^2(x)) ?
The solution to 1/(sin^2(x))+(sec^2(x))/(tan^2(x)) is 2csc^2(x)