What is (-7i)(-2+7i)(2+6i) ?

The solution to (-7i)(-2+7i)(2+6i) is 14+322i

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simplify (-7i)(-2+7i)(2+6i)

simplify

(- 7 i) (- 2 + 7 i) (2 + 6 i)

14 + 322 i

Solution steps

(- 7 i) (- 2 + 7 i) (2 + 6 i)

Apply complex arithmetic rule:

(a + bi) (c + d i) = (a c - b d) + (a d + b c) i

= - 7 i ((- 2 \cdot 2 - 7 \cdot 6) + (- 2 \cdot 6 + 7 \cdot 2) i)

Simplify

(- 2 \cdot 2 - 7 \cdot 6) + (- 2 \cdot 6 + 7 \cdot 2) i : - 46 + 2 i

= - 7 i (- 46 + 2 i)

Apply the distributive law:

a (b + c) = ab + a c

- 7 i (- 46 + 2 i) = - 7 i (- 46) - 7 i 2 i

= - 7 i (- 46) - 7 i 2 i

- 7 i (- 46) = 322 i

- 7 i 2 i = 14

= 322 i + 14

Rewrite in standard complex form:

14 + 322 i

= 14 + 322 i

(- 6)^{7}

\frac{5}{2} - \frac{6}{8}

(- 7 x^{4} + 7 x^{2} + 6 x - 8) - (9 x^{2} - 9 + 3 x^{5})

\frac{x ^{2} + x - 2}{x - 1}

12 m^{2} - 4 mn - 8 n^{2}