What is (x^3+5x^2)/(x^2+x-20) ?

The solution to (x^3+5x^2)/(x^2+x-20) is (x^2)/(x-4)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify (x^3+5x^2)/(x^2+x-20)

simplify

\frac{x ^{3} + 5 x ^{2}}{x ^{2} + x - 20}

\frac{x ^{2}}{x - 4}

Solution steps

\frac{x ^{3} + 5 x ^{2}}{x ^{2} + x - 20}

Factor

x^{3} + 5 x^{2} : x^{2} (x + 5)

= \frac{x ^{2} ( x + 5 )}{x ^{2} + x - 20}

Factor

x^{2} + x - 20 : (x - 4) (x + 5)

= \frac{x ^{2} ( x + 5 )}{( x - 4 ) ( x + 5 )}

Cancel the common factor:

x + 5

= \frac{x ^{2}}{x - 4}

\frac{9}{- 6}

\frac{9}{48}

(3 x + 2)^{2} + 8 (3 x + 2) + 12

x^{3} \cdot x

(\frac{1}{2} + \frac{3}{2} i)^{2 - 3 i}

What is (x^3+5x^2)/(x^2+x-20) ?
The solution to (x^3+5x^2)/(x^2+x-20) is (x^2)/(x-4)