What is log_{3}(1/81)+log_{1/3}(1/81) ?

The solution to log_{3}(1/81)+log_{1/3}(1/81) is 0

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simplify log_{3}(1/81)+log_{1/3}(1/81)

simplify

lo g_{3} (\frac{1}{81}) + lo g_{\frac{1}{3}} (\frac{1}{81})

0

Solution steps

lo g_{3} (\frac{1}{81}) + lo g_{\frac{1}{3}} (\frac{1}{81})

lo g_{3} (\frac{1}{81}) = - 4

lo g_{\frac{1}{3}} (\frac{1}{81}) = 4

= - 4 + 4

Add the numbers:

- 4 + 4 = 0

= 0

\frac{3 b ^{- 9}}{( 3 b ^{- 4} c ^{- 3} ) ^{- 3}}

(\frac{1}{2} a^{2} + \frac{3}{6} b) (\frac{1}{2} a^{2} - \frac{3}{6} b)

\frac{15}{39}

lo g_{10} (A^{n})

5 x + 6 x y - 7 x + 3 y + 12 x - 9 y + 12 x y + 10 x y

What is log_{3}(1/81)+log_{1/3}(1/81) ?
The solution to log_{3}(1/81)+log_{1/3}(1/81) is 0