What are the solutions to the equation r(14r+15)=0 ?

The solutions to the equation r(14r+15)=0 are r=0,r=-15/14

Find the zeros of r(14r+15)=0

The zeros of r(14r+15)=0 are r=0,r=-15/14

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r (14 r + 15) = 0

r = 0, r = - \frac{15}{14}

Solution steps

r (14 r + 15) = 0

Using the Zero Factor Principle:

ab = 0

then

a = 0

b = 0

r = 0 or 14 r + 15 = 0

Solve

14 r + 15 = 0 : r = - \frac{15}{14}

The solutions to the quadratic equation are:

r = 0, r = - \frac{15}{14}

3^{3}

1 < \frac{∣ x - 2 ∣}{∣ x + 3 ∣}

∣ 2 k - 1 ∣ \leq 2

x^{2} - 48 x + 576

4 x^{2} = 72

What are the solutions to the equation r(14r+15)=0 ?
The solutions to the equation r(14r+15)=0 are r=0,r=-15/14
Find the zeros of r(14r+15)=0
The zeros of r(14r+15)=0 are r=0,r=-15/14