What are the solutions to the equation 9x^2+12x-32=0 ?

The solutions to the equation 9x^2+12x-32=0 are x= 4/3 ,x=-8/3

Find the zeros of 9x^2+12x-32=0

The zeros of 9x^2+12x-32=0 are x= 4/3 ,x=-8/3

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9 x^{2} + 12 x - 32 = 0

x = \frac{4}{3}, x = - \frac{8}{3}

Solution steps

9 x^{2} + 12 x - 32 = 0

Solve with the quadratic formula

x_{1, 2} = \frac{- 12 \pm 1 2 ^{2} - 4 \cdot 9 ( - 32 )}{2 \cdot 9}

1 2^{2} - 4 \cdot 9 (- 32) = 36

x_{1, 2} = \frac{- 12 \pm 36}{2 \cdot 9}

Separate the solutions

x_{1} = \frac{- 12 + 36}{2 \cdot 9}, x_{2} = \frac{- 12 - 36}{2 \cdot 9}

x = \frac{- 12 + 36}{2 \cdot 9} : \frac{4}{3}

x = \frac{- 12 - 36}{2 \cdot 9} : - \frac{8}{3}

The solutions to the quadratic equation are:

x = \frac{4}{3}, x = - \frac{8}{3}

(x + 6)^{2} + 12 (x + 6) + 27 = 0

\frac{1}{8} + \frac{3}{4}

12 5^{\frac{1}{2}} \cdot 5^{\frac{1}{2}}

b^{2} - b - 2 = 0

\frac{x}{6} - \frac{x - 4}{2} = 0

What are the solutions to the equation 9x^2+12x-32=0 ?
The solutions to the equation 9x^2+12x-32=0 are x= 4/3 ,x=-8/3
Find the zeros of 9x^2+12x-32=0
The zeros of 9x^2+12x-32=0 are x= 4/3 ,x=-8/3