What is ((4/7)^2)/((7/4)^{-1)} ?

The solution to ((4/7)^2)/((7/4)^{-1)} is 4/7

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simplify ((4/7)^2)/((7/4)^{-1)}

simplify

\frac{( \frac{4}{7} ) ^{2}}{( \frac{7}{4} ) ^{- 1}}

\frac{4}{7}

Decimal Notation

0.57142 \dots

Solution steps

\frac{( \frac{4}{7} ) ^{2}}{( \frac{7}{4} ) ^{- 1}}

(\frac{7}{4})^{- 1} = \frac{4}{7}

= \frac{( \frac{4}{7} ) ^{2}}{\frac{4}{7}}

Apply exponent rule:

\frac{x ^{a}}{x ^{b}} = x^{a - b}

= (\frac{4}{7})^{2 - 1}

Subtract the numbers:

2 - 1 = 1

= (\frac{4}{7})^{1}

Apply exponent rule:

a^{1} = a

= \frac{4}{7}

\frac{x ^{2} + 8 x + 12}{x ^{2} - x - 42}

e^{l n (2)} + 2 ln (2)

\frac{\frac{7}{r - 5}}{\frac{26}{3 ( r ^{3} - 5 r ^{2} )}}

20 x^{10} - 125

\frac{a ^{2}}{7 b} \cdot \frac{21 b ^{3}}{2 a ^{4}}