What is the answer to z+(1/2+1/(sqrt(2))i)=i ?

The answer to z+(1/2+1/(sqrt(2))i)=i is z=-1/2+i(2-sqrt(2))/2

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z+(1/2+1/(sqrt(2))i)=i

z + (\frac{1}{2} + \frac{1}{2} i) = i

z = - \frac{1}{2} + i \frac{2 - 2}{2}

Solution steps

z + (\frac{1}{2} + \frac{1}{2} i) = i

Move

(\frac{1}{2} + \frac{1}{2} i)

to the right side

z = i \frac{2 - 1}{2} - \frac{1}{2}

Simplify

z = - \frac{1}{2} + i \frac{2 - 2}{2}

3 x^{2} + 5 x - 10 = 0

(\frac{1}{81})^{\frac{3}{4}}

100 \cdot 0.0 4^{2} = 0.0032 \cdot v^{2} + 100 \cdot 0.0 1^{2}

3 \cdot 18

9 x (2 x + 1) = 5

What is the answer to z+(1/2+1/(sqrt(2))i)=i ?
The answer to z+(1/2+1/(sqrt(2))i)=i is z=-1/2+i(2-sqrt(2))/2