What are the solutions to the equation 3x^2+15=0 ?

The solutions to the equation 3x^2+15=0 are x=sqrt(5)i,x=-sqrt(5)i

Find the zeros of 3x^2+15=0

The zeros of 3x^2+15=0 are x=sqrt(5)i,x=-sqrt(5)i

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3 x^{2} + 15 = 0

x = 5 i, x = - 5 i

Solution steps

3 x^{2} + 15 = 0

Move

15

to the right side

3 x^{2} = - 15

Divide both sides by

3

x^{2} = - 5

For

x^{2} = f (a)

the solutions are

x = f (a), - f (a)

x = - 5, x = - - 5

- 5 = 5 i

- - 5 = - 5 i

x = 5 i, x = - 5 i

x - 6 = 5 x - 2

x + 2 > 3 x - 8

x - 7 = 15

(\frac{8 ^{- 5}}{2 ^{- 2}})^{- 4}

5 x^{2} (2 x^{2} + 1)^{4} (6 x) + (2 x^{2} + 1)^{5} (2 x)

What are the solutions to the equation 3x^2+15=0 ?
The solutions to the equation 3x^2+15=0 are x=sqrt(5)i,x=-sqrt(5)i
Find the zeros of 3x^2+15=0
The zeros of 3x^2+15=0 are x=sqrt(5)i,x=-sqrt(5)i