What is expand ((2-x)^3)/3 ?

The solution to expand ((2-x)^3)/3 is -(x^3)/3+2x^2-4x+8/3

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expand ((2-x)^3)/3

expand

\frac{( 2 - x ) ^{3}}{3}

- \frac{x ^{3}}{3} + 2 x^{2} - 4 x + \frac{8}{3}

Solution steps

\frac{( 2 - x ) ^{3}}{3}

(2 - x)^{3} = 8 - 12 x + 6 x^{2} - x^{3}

= \frac{8 - 12 x + 6 x ^{2} - x ^{3}}{3}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{8 - 12 x + 6 x ^{2} - x ^{3}}{3} = \frac{8}{3} - \frac{12 x}{3} + \frac{6 x ^{2}}{3} - \frac{x ^{3}}{3}

= \frac{8}{3} - \frac{12 x}{3} + \frac{6 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{12}{3} = 4

= \frac{8}{3} - 4 x + \frac{6 x ^{2}}{3} - \frac{x ^{3}}{3}

Divide the numbers:

\frac{6}{3} = 2

= \frac{8}{3} - 4 x + 2 x^{2} - \frac{x ^{3}}{3}

Rewrite in standard form

= - \frac{x ^{3}}{3} + 2 x^{2} - 4 x + \frac{8}{3}

(x - 1 + 3) (x - 1 - 3)

(\frac{8}{5} a + \frac{1}{3} b)^{2}

lo g_{6} (3 m n^{8})

- \frac{8 x}{( x ^{2} - 4 ) ^{2}}

(3 - i)^{4}

What is expand ((2-x)^3)/3 ?
The solution to expand ((2-x)^3)/3 is -(x^3)/3+2x^2-4x+8/3