What is expand (5x^2-36x+48)/(x(x-4)^2) ?

The solution to expand (5x^2-36x+48)/(x(x-4)^2) is (5x^2-36x+48)/(x^3-8x^2+16x)

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expand (5x^2-36x+48)/(x(x-4)^2)

expand

\frac{5 x ^{2} - 36 x + 48}{x ( x - 4 ) ^{2}}

\frac{5 x ^{2} - 36 x + 48}{x ^{3} - 8 x ^{2} + 16 x}

Solution steps

\frac{5 x ^{2} - 36 x + 48}{x ( x - 4 ) ^{2}}

(x - 4)^{2} = x^{2} - 8 x + 16

= \frac{5 x ^{2} - 36 x + 48}{x ( x ^{2} - 8 x + 16 )}

Expand

x (x^{2} - 8 x + 16) : x^{3} - 8 x^{2} + 16 x

= \frac{5 x ^{2} - 36 x + 48}{x ^{3} - 8 x ^{2} + 16 x}

\frac{x ^{2} ( x + 1 ) ^{3}}{( x - 2 ) ^{2} ( x - 4 ) ^{4}}

(x^{2} + \frac{1}{x})^{3}

\frac{1}{( 2 + x ) ^{2}}

- \frac{3 u ^{2} + 2 u - 2}{u ( u ^{3} - 1 )}

8 cos^{2} (2 t) + (t - 5)^{2} - 7 e^{4 t}

What is expand (5x^2-36x+48)/(x(x-4)^2) ?
The solution to expand (5x^2-36x+48)/(x(x-4)^2) is (5x^2-36x+48)/(x^3-8x^2+16x)