What is expand (8x-1)/((x-2)(x+3)) ?

The solution to expand (8x-1)/((x-2)(x+3)) is (8x-1)/(x^2+x-6)

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expand (8x-1)/((x-2)(x+3))

expand

\frac{8 x - 1}{( x - 2 ) ( x + 3 )}

\frac{8 x - 1}{x ^{2} + x - 6}

Solution steps

\frac{8 x - 1}{( x - 2 ) ( x + 3 )}

Expand

(x - 2) (x + 3) : x^{2} + x - 6

= \frac{8 x - 1}{x ^{2} + x - 6}

(4 + \frac{1}{x}) (2 - \frac{3}{x})

\frac{( 1 + j ) ^{6}}{( 1 - j ) ^{2} ( 2 + j ) ^{4}}

(3 x - 2)^{2}

(cos (θ) + i sin (θ))^{5}

2 (\frac{5}{e ^{4}} + \frac{5}{e ^{16}} + \frac{5}{e ^{36}})

What is expand (8x-1)/((x-2)(x+3)) ?
The solution to expand (8x-1)/((x-2)(x+3)) is (8x-1)/(x^2+x-6)