What are the solutions to the equation y^2+2y-24=0 ?

The solutions to the equation y^2+2y-24=0 are y=4,y=-6

Find the zeros of y^2+2y-24=0

The zeros of y^2+2y-24=0 are y=4,y=-6

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

y^{2} + 2 y - 24 = 0

y = 4, y = - 6

Solution steps

y^{2} + 2 y - 24 = 0

Solve with the quadratic formula

y_{1, 2} = \frac{- 2 \pm 2 ^{2} - 4 \cdot 1 \cdot ( - 24 )}{2 \cdot 1}

2^{2} - 4 \cdot 1 \cdot (- 24) = 10

y_{1, 2} = \frac{- 2 \pm 10}{2 \cdot 1}

Separate the solutions

y_{1} = \frac{- 2 + 10}{2 \cdot 1}, y_{2} = \frac{- 2 - 10}{2 \cdot 1}

y = \frac{- 2 + 10}{2 \cdot 1} : 4

y = \frac{- 2 - 10}{2 \cdot 1} : - 6

The solutions to the quadratic equation are:

y = 4, y = - 6

- 2 + 3 (\frac{2}{3}) \geq \frac{1}{3}

(t + \frac{1}{3}) (t + \frac{2}{3}) = 0

2 x - 4 \leq 12

\frac{a - 3}{9 a ^{3} - 27 a ^{2}} + 3

6 x^{2} - 14 x + 4

What are the solutions to the equation y^2+2y-24=0 ?
The solutions to the equation y^2+2y-24=0 are y=4,y=-6
Find the zeros of y^2+2y-24=0
The zeros of y^2+2y-24=0 are y=4,y=-6