What is expand (4x-1)/((x-2)(x+3)) ?

The solution to expand (4x-1)/((x-2)(x+3)) is (4x-1)/(x^2+x-6)

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expand (4x-1)/((x-2)(x+3))

expand

\frac{4 x - 1}{( x - 2 ) ( x + 3 )}

\frac{4 x - 1}{x ^{2} + x - 6}

Solution steps

\frac{4 x - 1}{( x - 2 ) ( x + 3 )}

Expand

(x - 2) (x + 3) : x^{2} + x - 6

= \frac{4 x - 1}{x ^{2} + x - 6}

(x^{2} + a x - 1 - x^{2} - a x + 1) \cdot (x^{2} + a x - 1 + x^{2} - a x + 1)

(\frac{2 x}{3} - \frac{2}{y})^{4}

(2 - 3 i)^{5}

e^{t} (cos (2 t) - sin (2 t))^{2}

lo g_{10} (4) x^{3}

What is expand (4x-1)/((x-2)(x+3)) ?
The solution to expand (4x-1)/((x-2)(x+3)) is (4x-1)/(x^2+x-6)