What is expand (pik(b^2+z^2-2bz))/(2a) ?

The solution to expand (pik(b^2+z^2-2bz))/(2a) is (pib^2k}{2a}+(pikz^2)/(2a)-\frac{pibkz)/a

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expand (pik(b^2+z^2-2bz))/(2a)

expand

\frac{πk ( b ^{2} + z ^{2} - 2 b z )}{2 a}

\frac{π b ^{2} k}{2 a} + \frac{πk z ^{2}}{2 a} - \frac{πbk z}{a}

Solution steps

\frac{πk ( b ^{2} + z ^{2} - 2 b z )}{2 a}

Expand

πk (b^{2} + z^{2} - 2 b z) : π b^{2} k + πk z^{2} - 2 πbk z

= \frac{π b ^{2} k + πk z ^{2} - 2 πbk z}{2 a}

Apply the fraction rule:

\frac{a \pm b}{c} = \frac{a}{c} \pm \frac{b}{c}

\frac{π b ^{2} k + πk z ^{2} - 2 πbk z}{2 a} = \frac{π b ^{2} k}{2 a} + \frac{πk z ^{2}}{2 a} - \frac{2 πbk z}{2 a}

= \frac{π b ^{2} k}{2 a} + \frac{πk z ^{2}}{2 a} - \frac{2 πbk z}{2 a}

Divide the numbers:

\frac{2}{2} = 1

= \frac{π b ^{2} k}{2 a} + \frac{πk z ^{2}}{2 a} - \frac{πbk z}{a}

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(x - 7)^{2}

What is expand (pik(b^2+z^2-2bz))/(2a) ?
The solution to expand (pik(b^2+z^2-2bz))/(2a) is (pib^2k}{2a}+(pikz^2)/(2a)-\frac{pibkz)/a