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Popular >

expand (x-3)(x+1)'

Solution

expand

(x - 3) (x + 1)^{'}

Solution

x (x + 1)' - 3 (x + 1)'

Solution steps

(x - 3) (x + 1)^{'}

Apply the distributive law:

a (b - c) = ab - a c

a = (x + 1)^{'}, b = x, c = 3

= (x + 1)^{^{'}} x - (x + 1)^{^{'}} 3

= x (x + 1)^{^{'}} - 3 (x + 1)^{^{'}}

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Frequently Asked Questions (FAQ)

What is expand (x-3)(x+1)' ?
The solution to expand (x-3)(x+1)' is x(x+1)'-3(x+1)'