What is ((3i)/n-2)^2 ?

The solution to ((3i)/n-2)^2 is (4n^2-9}{n^2}-\frac{12)/n i

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

Popular >

simplify ((3i)/n-2)^2

simplify

(\frac{3 i}{n} - 2)^{2}

\frac{4 n ^{2} - 9}{n ^{2}} - \frac{12}{n} i

Solution steps

(\frac{3 i}{n} - 2)^{2}

Apply Perfect Square Formula:

(a - b)^{2} = a^{2} - 2 ab + b^{2}

(\frac{3 i}{n} - 2)^{2} = (\frac{3 i}{n})^{2} - 2 \cdot \frac{3 i}{n} \cdot 2 + 2^{2}

= (\frac{3 i}{n})^{2} - 2 \cdot \frac{3 i}{n} \cdot 2 + 2^{2}

(\frac{3 i}{n})^{2} = - \frac{9}{n ^{2}}

2 \cdot \frac{3 i}{n} \cdot 2 = 4 \cdot \frac{3 i}{n}

2^{2} = 4

= - \frac{9}{n ^{2}} - 4 \cdot \frac{3 i}{n} + 4

Simplify

- \frac{9}{n ^{2}} - 4 \cdot \frac{3 i}{n} + 4 : \frac{4 n ^{2} - 9}{n ^{2}} - \frac{12}{n} i

= \frac{4 n ^{2} - 9}{n ^{2}} - \frac{12}{n} i

(a + bi)^{5}

2 (3 e^{- x} x^{2} - e^{- x} x^{3})

cos (7 t) (5 + sinh (3 t) + e^{2 t})

\frac{d}{d t} ((h (t)) (2.8 t + 2.5))

(4 + 5 y i)^{2}

What is ((3i)/n-2)^2 ?
The solution to ((3i)/n-2)^2 is (4n^2-9}{n^2}-\frac{12)/n i