What is (sqrt(3x-8)+1)^2 ?

The solution to (sqrt(3x-8)+1)^2 is 3x+2sqrt(3x-8)-7

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simplify (sqrt(3x-8)+1)^2

simplify

(3 x - 8 + 1)^{2}

3 x + 2 3 x - 8 - 7

Solution steps

(3 x - 8 + 1)^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(3 x - 8 + 1)^{2} = (3 x - 8)^{2} + 2 3 x - 8 \cdot 1 + 1^{2}

= (3 x - 8)^{2} + 2 3 x - 8 \cdot 1 + 1^{2}

Simplify

(3 x - 8)^{2} + 2 3 x - 8 \cdot 1 + 1^{2} : 3 x + 2 3 x - 8 - 7

= 3 x + 2 3 x - 8 - 7

(2 x^{2} - \frac{1}{x})^{6}

7 \cdot (9 + 2)

x^{\frac{1}{3}} (x^{2} - 4)

\frac{10}{( s + 2 ) ( s + 1 ) ^{3}}

5 (10 + 2)