What is expand e^{kt}(5-bt+4sin(t/a)) ?

The solution to expand e^{kt}(5-bt+4sin(t/a)) is 5e^{kt}-e^{kt}tb+4e^{kt}sin(t/a)

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expand e^{kt}(5-bt+4sin(t/a))

expand

e^{k t} (5 - b t + 4 sin (\frac{t}{a}))

5 e^{k t} - e^{k t} t b + 4 e^{k t} sin (\frac{t}{a})

Solution steps

e^{k t} (5 - b t + 4 sin (\frac{t}{a}))

= e^{k t} (5 - t b + 4 sin (\frac{t}{a}))

Distribute parentheses

= e^{k t} \cdot 5 + e^{k t} (- b t) + e^{k t} \cdot 4 sin (\frac{t}{a})

Apply minus-plus rules

+ (- a) = - a

= 5 e^{k t} - e^{k t} t b + 4 e^{k t} sin (\frac{t}{a})

(2 x y - sec^{2} (x)) d x + (x^{2} + 2 y) d y

(2 - 2 cos (x))^{2}

(y^{2} + 1 + 3) (y^{2} + 1 - 3)

(5 x - 2) (5 x + 2)

(x - 1 + 6) (x - 1 - 6)

What is expand e^{kt}(5-bt+4sin(t/a)) ?
The solution to expand e^{kt}(5-bt+4sin(t/a)) is 5e^{kt}-e^{kt}tb+4e^{kt}sin(t/a)