What is (2+(4i)/n)^2 ?

The solution to (2+(4i)/n)^2 is (4n^2-16}{n^2}+\frac{16)/n i

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simplify (2+(4i)/n)^2

simplify

(2 + \frac{4 i}{n})^{2}

\frac{4 n ^{2} - 16}{n ^{2}} + \frac{16}{n} i

Solution steps

(2 + \frac{4 i}{n})^{2}

Apply Perfect Square Formula:

(a + b)^{2} = a^{2} + 2 ab + b^{2}

(2 + \frac{4 i}{n})^{2} = 2^{2} + 2 \cdot 2 \cdot \frac{4 i}{n} + (\frac{4 i}{n})^{2}

= 2^{2} + 2 \cdot 2 \cdot \frac{4 i}{n} + (\frac{4 i}{n})^{2}

Simplify

2^{2} + 2 \cdot 2 \cdot \frac{4 i}{n} + (\frac{4 i}{n})^{2} : \frac{4 n ^{2} - 16}{n ^{2}} + \frac{16}{n} i

= \frac{4 n ^{2} - 16}{n ^{2}} + \frac{16}{n} i

(x^{2} + y^{2}) (x^{2} + y^{2})

(x - y arctan (\frac{y}{x})) d x + x arctan (\frac{y}{x}) d y

3 (2^{\frac{1}{3}} - 1)

e^{0}

- e^{3} f^{2} (e^{2} f^{5} + e - 4 f^{2})

What is (2+(4i)/n)^2 ?
The solution to (2+(4i)/n)^2 is (4n^2-16}{n^2}+\frac{16)/n i